CBSE Class 12 Physics — Dual Nature of Radiation and Matter

Assertion (A): If accelerated electrons are passed through a narrow slit, a diffraction pattern is observed. Reason (R): Electrons behave as both particles and waves.

In a photoelectric experiment, the emitter plate is irradiated with radiation of 200 nm. The photocurrent becomes zero when the collector plate potential is − 0.80 V. Calculate the work function (in eV) of the emitter.

From the graph, the work functions of A and B are (h is Planck's constant and e value of charge on an electron)

For radiation of frequency $\nu > \nu_2$ incident on the surfaces of A and B, the maximum kinetic energy of ejected electron is

If the intensity of the incident radiation for both metals A and B, is doubled keeping its frequency constant, then

The threshold frequency for a metal surface is $\nu_0$. If the radiation of frequency $3\nu_0$ illuminates the surface, the maximum kinetic energy (KE) of photoelectrons is $E_1$. If the frequency were increased to $6\nu_0$, the maximum KE of the photoelectrons becomes $E_2$. Then $(E_1/E_2)$ equals OR Let m be the slope of the graph line for metal B. If e is the value of electron charge, then Planck's constant 'h' is given by (A) $me$ (B) $1/(me)$ (C) $m/e$ (D) $e/m$