If and , then is equal to :
If and , then is equal to :
Options
Official answer
The correct option is D) 2B.
Working:
- Given and .
- Compute using : .
- Hence (B is idempotent).
- Therefore .
Marking scheme
- 1.1 mark: showing and concluding (option D).
Hint
Write , then and regroup as ; use .
Quick oral answer
Substituting gives , so B is idempotent and .
Common mistakes
- 1.Assuming implies A is the identity or B is the identity — it does not.
- 2.Treating matrix multiplication as commutative and writing .
- 3.Stopping at without adding B to reach .
Analysis and explanation
This tests careful use of the associative property of matrix multiplication and the idempotent idea.
Concept:
- A matrix M is idempotent if . The two given relations force exactly this for B.
- Key manipulation: substitute one factor using a given relation, then regroup with associativity.
Why D is correct:
- , so .
Why the distractors are wrong:
- A (): would need , but , not A.
- B (O): would require , which the relations do not give.
- C (): assumes B is the identity; B is only idempotent, not necessarily I.
Interesting facts
Idempotent matrices () are exactly the projection matrices used in statistics and computer graphics.
The pair , makes both A and B idempotent, and they act like mutual identities on each other's column space.
Question details
Q3 of 44 questions
- Board
- CBSE
- Class
- Class 12
- Subject
- Applied Mathematics
- Year
- 2026
- Section
- Section A
- Marks
- 1
- Type
- MCQ
- Chapter
- Algebra (Matrices)
- Topic
- Matrix Algebra — idempotent matrices
- Bloom's level
- analyze
- Syllabus topic
- Unit 2: Algebra — Matrices: multiplication and idempotent property
- Author
- CBSE
- Reviewed by
- Padhantu Academic Team
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Frequently asked questions
What does it mean that B is idempotent?
It means — multiplying B by itself returns B. The conditions and force this property on B.
Can we conclude B is the identity matrix?
No. B is only idempotent. The identity is one special idempotent matrix, but many non-identity idempotent matrices exist, so does not make B equal to I.