Question 141 markMCQSection A

An electric iron of resistance 20Ω20 \Omega draws a current of 5 A5 \mathrm{~A}. The heat developed in the iron in 30 seconds is :

Electricity
Electricity

Options

(A)15000 J
(B)6000 J
(C)1500 J
(D)3000 J

Official answer

Heat developed in the iron is given by H=I2Rt=(5)2(20)(30)=15000extJH = I^2 R t = (5)^2 (20) (30) = 15000 ext{ J}

Answer keywords:Heat developedelectric ironresistancecurrenttime

Marking scheme

  1. 1.1 mark

Hint

Use the formula H=I2RtH = I^2 R t to calculate the heat developed in the iron.

Quick oral answer

The heat developed in the iron is 15000 J.

Common mistakes

  1. 1.None

Analysis and explanation

The heat developed in the iron is directly proportional to the square of the current, the resistance, and the time. Therefore, the heat developed is maximum when the current is maximum, the resistance is maximum, and the time is maximum.

Interesting facts

The heat developed in the iron is directly proportional to the square of the current, the resistance, and the time.

Question details

Q14 of 39 questions

Board
CBSE
Class
Class 10
Subject
Science
Year
2024
Section
Section A
Marks
1
Type
MCQ
Chapter
Electricity
Topic
Electricity
Bloom's level
Remembering
Syllabus topic
Electricity

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Frequently asked questions

How many marks does this question carry in CBSE Class 10 Science 2024?

This question carries 1 mark in the CBSE Class 10 Science 2024 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Electricity" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Electricity" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2024 paper?

This is a MCQ question from Section A in the CBSE Class 10 Science 2024 paper.