(a) A saturated organic compound 'A' belongs to the homologous series of alcohols. On heating 'A' with concentrated sulphuric acid at 443 K, it forms an unsaturated compound 'B' with molecular mass 28 u. The compound 'B' on addition of one mole of hydrogen in the presence of Nickel, changes to a saturated hydrocarbon 'C'. (i) Identify A, B and C. (ii) Write the chemical equations showing the conversion of A into B. (iii) What happens when compound C undergoes combustion? (iv) State one industrial application of hydrogenation reaction. (v) Name the products formed when compound A reacts with sodium. OR (b) (i) With the help of diagram, show the formation of micelles, when soap is applied on oily dirt. (ii) Take two test tubes X and Y with of hard water in each. In test tube 'X', add few drops of soap solution and in test tube 'Y' add a few drops of detergent solution. Shake both the test tubes for the same period. (1) In which test tube the formation of foam will be more? Why? (2) In which test tube is a curdy solid formed? Why?
(a) A saturated organic compound 'A' belongs to the homologous series of alcohols. On heating 'A' with concentrated sulphuric acid at 443 K, it forms an unsaturated compound 'B' with molecular mass 28 u. The compound 'B' on addition of one mole of hydrogen in the presence of Nickel, changes to a saturated hydrocarbon 'C'. (i) Identify A, B and C. (ii) Write the chemical equations showing the conversion of A into B. (iii) What happens when compound C undergoes combustion? (iv) State one industrial application of hydrogenation reaction. (v) Name the products formed when compound A reacts with sodium. OR (b) (i) With the help of diagram, show the formation of micelles, when soap is applied on oily dirt. (ii) Take two test tubes X and Y with of hard water in each. In test tube 'X', add few drops of soap solution and in test tube 'Y' add a few drops of detergent solution. Shake both the test tubes for the same period. (1) In which test tube the formation of foam will be more? Why? (2) In which test tube is a curdy solid formed? Why?
PART (a)
(i) Identification of A, B, and C:
- Compound A is Ethanol ( or ).
- Compound B is Ethene ( or ). Its molecular mass is calculated as:
- Compound C is Ethane ( or ).
(ii) Chemical Equation for the conversion of A into B (Dehydration):
(Here, concentrated sulphuric acid acts as a dehydrating agent.)
(iii) Combustion of Compound C (Ethane):
When ethane undergoes complete combustion in the presence of oxygen, it burns with a clean blue flame to produce carbon dioxide gas, water vapor, heat, and light.
(iv) Industrial Application of Hydrogenation:
Hydrogenation is used industrially to convert liquid vegetable oils (unsaturated fats) into solid vanaspati ghee (saturated fats) using a nickel () catalyst.
(v) Reaction of Compound A (Ethanol) with Sodium:
When ethanol reacts with sodium metal, it forms sodium ethoxide and releases hydrogen gas.
PART (b)
(i) Micelle Formation:
Soap molecules consist of two parts:
- A hydrophilic (water-loving) ionic head (e.g., ) which points outwards towards water.
- A hydrophobic (water-fearing) hydrocarbon tail which points inwards, away from water, attaching itself to the oily dirt.
When soap is applied to oily dirt, the hydrophobic tails align towards the center to dissolve in the oil droplet, while the ionic heads face outwards into the aqueous medium. This unique spherical cluster of soap molecules trapping the dirt at the center is called a micelle.
(ii) Test Tube X (Soap + Hard Water) vs Test Tube Y (Detergent + Hard Water):
- More Foam Formation: Test tube Y will show more foam formation. Detergents are sodium salts of sulfonic acids or ammonium salts with chlorides or bromides. Their charged ends do not form insoluble precipitates with the calcium () and magnesium () ions present in hard water. Thus, they remain effective and lather easily.
- Curdy Solid Formation: Test tube X will show the formation of a curdy solid (scum). Soap reacts with the calcium and magnesium salts present in hard water to form insoluble calcium and magnesium salts of fatty acids, which precipitate out as a sticky, curdy white solid.
Marking Scheme
- 1Part (a):
- 20.5 mark each for identifying A (Ethanol), B (Ethene), and C (Ethane) [Total: 1.5 marks]
- 31 mark for the balanced chemical equation of dehydration of ethanol with conditions.
- 41 mark for the balanced combustion equation of ethane.
- 50.5 mark for stating the industrial hydrogenation of vegetable oils.
- 61 mark for the balanced equation of ethanol reacting with sodium.
- 7OR
- 8Part (b):
- 91 mark for a neat labeled diagram of a micelle.
- 101 mark for explaining the hydrophilic and hydrophobic parts of a soap molecule.
- 111.5 marks for identifying test tube Y as having more foam and explaining why detergents do not form precipitates with hard water ions.
- 121.5 marks for identifying test tube X as forming a curdy solid and explaining the reaction of soap with and ions to form scum.
Hint
- For (a), calculate the molecular mass of ethene () to confirm B. Remember that hot conc. at is a standard dehydrating agent. - For (b), remember that detergents are designed to work effectively in hard water without forming scum, whereas soaps form an insoluble precipitate.
Quick Oral Answer
Ethanol is dehydrated to ethene using hot concentrated sulphuric acid at 443 K. When soap is added to hard water, it forms a curdy white precipitate called scum because soap reacts with the calcium and magnesium ions present in the hard water.
Analysis & Explanation
This question tests the core chemical properties of carbon compounds and the practical applications of cleansing agents:
- Dehydration of Alcohols: Concentrated acts as a strong dehydrating agent because of its high affinity for water, removing a water molecule from adjacent carbon atoms in ethanol to establish a double bond.
- Addition Reaction (Hydrogenation): Unsaturated hydrocarbons add hydrogen in the presence of catalysts like Palladium or Nickel to give saturated hydrocarbons. This is a key industrial process to solidify plant-based oils.
- Cleansing Action of Soaps: Hard water contains dissolved calcium and magnesium hydrogen carbonates, sulfates, or chlorides. Soaps are sodium/potassium salts of long-chain carboxylic acids which precipitate out as calcium/magnesium salts (scum), wasting soap and reducing lather. Detergents overcome this limitation because their polar heads do not bind precipitously with or ions.
Common Mistakes
- 1Forgetting to write the reaction conditions (such as and conc. ) over the arrow in the dehydration reaction.
- 2Confusing the products of the reaction of ethanol with sodium; writing sodium oxide instead of sodium ethoxide.
- 3Inverting the orientation of soap molecules in a micelle (drawing the ionic heads pointing towards the oil instead of outwards).
Interesting Facts
Soap does not actually kill germs on our hands; instead, the micelles encapsulate the grease, dirt, and microbes, allowing them to be easily rinsed away by water due to the outer hydrophilic heads.
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Frequently Asked Questions
How many marks does this question carry in CBSE Class 10 Science 2023?
This question carries 5 marks in the CBSE Class 10 Science 2023 examination.
Which chapter does this question come from in Science?
This question is from the chapter "Carbon and its Compounds" in the CBSE Class 10 Science syllabus.
What topic does this question cover in Science?
This question covers the topic "Chemical Properties of Carbon Compounds & Soaps and Detergents" from CBSE Class 10 Science.
What type of question is this in the CBSE Class 10 Science 2023 paper?
This is a Long Answer question from Section D in the CBSE Class 10 Science 2023 paper.