Question 265 marksLong AnswerSection C

(a) (i) Write two properties of gold which make it the most suitable metal for ornaments. (ii) Name two metals which are the best conductors of heat. (iii) Name two metals which melt when you keep them on your palm. (b) Explain the formation of ionic compound CaO with electron-dot structure. Atomic numbers of calcium and oxygen are 20 and 8 respectively.

Metals and Non-metals
Physical Properties of Metals and Formation of Ionic Compounds

Official answer

Part (a)


(i) Two properties of gold which make it the most suitable metal for ornaments:

  1. High Malleability and Ductility: Gold is the most malleable and ductile metal known. A wire of about 2 km2\text{ km} length can be drawn from just one gram of gold, allowing artisans to design highly intricate and delicate patterns.
  2. Chemical Inertness (Corrosion Resistance) and Lustre: Gold has a brilliant, long-lasting metallic lustre and does not react with oxygen, moisture, or acids even at high temperatures. This ensures that ornaments do not tarnish or corrode over time.

(ii) Two metals which are the best conductors of heat:

  • Silver (AgAg) and Copper (CuCu).

(iii) Two metals which melt when kept on the palm:

  • Gallium (GaGa) and Caesium (CsCs).



Part (b) Formation of Ionic Compound CaOCaO (Calcium Oxide)


1. Electronic Configurations:

  • Calcium (CaCa, Atomic Number = 2020):
  • Electronic configuration: 2,8,8,22, 8, 8, 2
  • Valence electrons: 22
  • To achieve a stable octet configuration, a calcium atom loses its 22 valence electrons to form a calcium cation (Ca2+Ca^{2+}):

Ca→Ca2++2e−Ca \rightarrow Ca^{2+} + 2e^{-}

(2, 8, 8, 2)→(2, 8, 8)\text{(2, 8, 8, 2)} \rightarrow \text{(2, 8, 8)}


  • Oxygen (OO, Atomic Number = 88):
  • Electronic configuration: 2,62, 6
  • Valence electrons: 66
  • To achieve a stable octet configuration, an oxygen atom gains 22 electrons to form an oxide anion (O2−O^{2-}):

O+2e−→O2−O + 2e^{-} \rightarrow O^{2-}

(2, 6)→(2, 8)\text{(2, 6)} \rightarrow \text{(2, 8)}


2. Electron-Dot Transfer Diagram:


Calcium transfers its 22 valence electrons to the oxygen atom, which requires 22 electrons to complete its octet:


Ca∙∙+⋅⋅ O¨ ⋅⋅⟶Ca2+[:O¨:]2− or CaO\text{Ca}^{\bullet \bullet} + \cdot \cdot \ \ddot{\text{O}} \ \cdot \cdot \longrightarrow \text{Ca}^{2+} \left[ :\ddot{\text{O}}: \right]^{2-} \text{ or } \text{CaO}

Answer keywords:MalleabilityDuctilityLustreCorrosion resistantSilverCopperGalliumCaesiumElectronic configurationOctetElectron transferCalcium cationOxide anion

Marking scheme

  1. 1.1 mark
  2. 2.1 mark
  3. 3.1 mark
  4. 4.1 mark
  5. 5.1 mark

Hint

For part (b), write down the electronic configurations of Calcium (2,8,8,22, 8, 8, 2) and Oxygen (2,62, 6) first. Show the transfer of 22 electrons from CaCa to OO using arrows, and don't forget to write the final charges on the ions.

Quick oral answer

Q: What type of chemical bond is present in Calcium Oxide (CaOCaO)? A: It contains an ionic bond (or electrovalent bond) formed by the complete transfer of two electrons from a calcium atom to an oxygen atom.

Common mistakes

  1. 1.Writing incorrect electronic configurations for Calcium (e.g., 2,8,102, 8, 10 instead of 2,8,8,22, 8, 8, 2).
  2. 2.Forgetting to show the charges (2+2+ and 2−2-) on the ions in the final electron-dot structure.
  3. 3.Confusing the best conductors of heat (Silver and Copper) with the best conductors of electricity or poor conductors like Lead and Mercury.

Analysis and explanation

This question integrates the physical properties of metals with the chemical concept of ionic bond formation.

  • Physical Properties: Gold's extreme ductility and resistance to oxidation make it ideal for jewelry. Silver and copper have free electrons that make them excellent thermal conductors. Gallium and caesium have exceptionally low melting points (29.76∘C29.76^\circ\text{C} and 28.44∘C28.44^\circ\text{C} respectively), which are below human body temperature (37∘C37^\circ\text{C}), causing them to melt on a warm palm.
  • Chemical Bonding: Calcium (a metal) has a low ionization energy and readily loses 22 electrons to achieve a stable noble gas configuration (ArAr). Oxygen (a non-metal) has high electron affinity and gains these 22 electrons to achieve the stable configuration of Neon (NeNe). The electrostatic attraction between the oppositely charged ions (Ca2+Ca^{2+} and O2−O^{2-}) forms the ionic compound CaOCaO.

Interesting facts

Gallium is a metal that will literally melt in your hand, but if you try to boil it, it won't turn into gas until it reaches 2204∘C2204^\circ\text{C}, giving it one of the largest liquid ranges of any element!

A single gram of gold can be beaten into a sheet covering nearly one square meter.

Question details

Q26 of 30 questions

Board
CBSE
Class
Class 10
Subject
Science
Year
2020
Section
Section C
Marks
5
Type
Long Answer
Chapter
Metals and Non-metals
Topic
Physical Properties of Metals and Formation of Ionic Compounds
Bloom's level
Applying
Syllabus topic
Physical properties of metals, chemical properties, ionic compounds (formation and properties)

Spotted a mistake or something unclear?

Tell us and we will fix it.

Frequently asked questions

How many marks does this question carry in CBSE Class 10 Science 2020?

This question carries 5 marks in the CBSE Class 10 Science 2020 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Metals and Non-metals" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Physical Properties of Metals and Formation of Ionic Compounds" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2020 paper?

This is a Long Answer question from Section C in the CBSE Class 10 Science 2020 paper.