Q21
3 marksShort AnswerSection B

A concave mirror is used for image formation for different positions of an object. What inferences can be drawn about the following when an object is placed at a distance of 10 cm10\text{ cm} from the pole of a concave mirror of focal length 15 cm15\text{ cm}?

(a) Position of the image

(b) Size of the image

(c) Nature of the image

Draw a labelled ray diagram to justify your inferences.

Light — Reflection and Refraction
Image Formation by Concave Mirror
Official Answer

When an object is placed at a distance of 10 cm10\text{ cm} from a concave mirror of focal length 15 cm15\text{ cm}, the object lies between the pole (PP) and the principal focus (FF) of the mirror (since u<fu < f).


Based on the principles of reflection and Table 9.1 of the NCERT textbook, the inferences are:

(a) Position of the image: Behind the mirror (at a distance of 30 cm30\text{ cm} from the pole).

(b) Size of the image: Enlarged (magnified by a factor of 33).

(c) Nature of the image: Virtual and erect.


Ray Diagram:

``

M

|\

A | \ A'

\
\

------B-------P----F'-B'------ (Principal Axis)

C F | /

| /

N/

``

(In this diagram, the object ABAB is placed between PP and FF. Ray 1 parallel to the principal axis reflects through FF. Ray 2 passing through CC reflects back along CC. When produced backwards, these rays meet at AA' behind the mirror to form the virtual, erect, and enlarged image ABA'B'.)

Behind the mirrorEnlargedVirtual and erectMirror formulaBetween P and F

Marking Scheme

  • 1State that the object lies between the pole and focus of the concave mirror. (0.5 marks)
  • 2Correctly calculate the image distance (v=+30 cmv = +30\text{ cm}) using the mirror formula. (1 mark)
  • 3State the correct characteristics: Position (behind the mirror), Size (enlarged), and Nature (virtual and erect). (0.5 marks)
  • 4Draw a neat, labelled ray diagram showing the object between PP and FF with virtual rays meeting behind the mirror. (1 mark)

Hint

Since the object distance (10 cm10\text{ cm}) is less than the focal length (15 cm15\text{ cm}), the object is between PP and FF. Use the mirror formula 1v+1u=1f\frac{1}{v} + \frac{1}{u} = \frac{1}{f} to find the exact position and nature.

Quick Oral Answer

When an object is placed within the focal length of a concave mirror, it forms a virtual, erect, and magnified image behind the mirror because the reflected rays diverge in front and only appear to meet when extended backwards.

Analysis & Explanation

According to Table 9.1 of the NCERT textbook, when an object is placed between the pole (PP) and the focus (FF) of a concave mirror, the image is formed behind the mirror. This is the only position for a concave mirror where a virtual, erect, and magnified image is produced. This property makes concave mirrors highly useful as shaving mirrors or dentist mirrors, where a magnified and upright view of an object is required.

Common Mistakes

  1. 1Forgetting to apply the proper sign convention (e.g., taking uu as positive instead of negative).
  2. 2Drawing solid lines behind the mirror instead of dashed lines for virtual rays.
  3. 3Confusing the focal length of a concave mirror as positive.

Interesting Facts

This specific configuration is the only case where a concave mirror behaves like a magnifying glass, producing a virtual and erect image instead of a real and inverted one.

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Frequently Asked Questions

How many marks does this question carry in CBSE Class 10 Science 2020?

This question carries 3 marks in the CBSE Class 10 Science 2020 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Light — Reflection and Refraction" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Image Formation by Concave Mirror" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2020 paper?

This is a Short Answer question from Section B in the CBSE Class 10 Science 2020 paper.