2 g of silver chloride is taken in a china dish and the china dish is placed in sunlight for sometime. What will be your observation in this case? Write the chemical reaction involved in the form of a balanced chemical equation. Identify the type of chemical reaction.

In part (a), zinc ($Zn$) is placed higher in the reactivity series than silver ($Ag$). Thus, it displaces silver from silver nitrate ($AgNO_3$) to form zinc nitrate ($Zn(NO_3)_2$) and metallic silver. This is a single displacement reaction.

In part (b), which corresponds to Activity 1.2 in the NCERT textbook, lead nitrate ($Pb(NO_3)_2$) and potassium iodide ($KI$) exchange their ionic partners ($Pb^{2+}$ with $I^-$ and $K^+$ with $NO_3^-$) to form a yellow precipitate of lead iodide ($PbI_2$) and soluble potassium nitrate ($KNO_3$). This mutual exchange of ions makes it a double displacement reaction.