(a) With the help of a suitable circuit diagram prove that the reciprocal of the equivalent resistance of a group of resistances joined in parallel is equal to the sum of the reciprocals of the individual resistances. (b) In an electric circuit two resistors of each are joined in parallel to a battery. Find the current drawn from the battery.
(a) With the help of a suitable circuit diagram prove that the reciprocal of the equivalent resistance of a group of resistances joined in parallel is equal to the sum of the reciprocals of the individual resistances. (b) In an electric circuit two resistors of each are joined in parallel to a battery. Find the current drawn from the battery.
The correct answer is (a) 24 \Omega.
Marking Scheme
- 1Total resistance of the circuit
- 2Current through the circuit
- 3Potential difference across the electric lamp
- 4Potential difference across the conductor
- 5Power of the lamp
Hint
Use Ohm's law to find the current through the circuit and then calculate the potential difference across each component.
Quick Oral Answer
The total resistance of the circuit is 24 \Omega. The current through the circuit is 0.25 A. The potential difference across the electric lamp is 5 V. The potential difference across the conductor is 1 V. The power of the lamp is 1.25 W.
Analysis & Explanation
The question requires us to calculate the total resistance of the circuit, which is the sum of the resistances of the electric lamp and the conductor. We can use Ohm's law to find the current through the circuit and then calculate the potential difference across each component.
Common Mistakes
- 1Forgetting to add the resistances of the electric lamp and the conductor
- 2Not using Ohm's law to find the current through the circuit
- 3Not calculating the potential difference across each component
Interesting Facts
The total resistance of the circuit is the sum of the resistances of the electric lamp and the conductor.
The current through the circuit can be found using Ohm's law.
The potential difference across each component can be calculated using Ohm's law.
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Frequently Asked Questions
How many marks does this question carry in CBSE Class 10 Science 2019?
This question carries 5 marks in the CBSE Class 10 Science 2019 examination.
Which chapter does this question come from in Science?
This question is from the chapter "Chemical Reactions and Equations" in the CBSE Class 10 Science syllabus.
What topic does this question cover in Science?
This question covers the topic "Chemical Reactions and Equations" from CBSE Class 10 Science.
What type of question is this in the CBSE Class 10 Science 2019 paper?
This is a Long Answer question from Section D in the CBSE Class 10 Science 2019 paper.