Write the molecular formula of the 2nd and 3rd member of the homologous series where the first member is ethyne.
Write the molecular formula of the 2nd and 3rd member of the homologous series where the first member is ethyne.
The molecular formula of the 2nd member is (propyne) and the 3rd member is (butyne).
Marking Scheme
- 1Identification of the 2nd member as : 0.5 mark
- 2Identification of the 3rd member as : 0.5 mark
Hint
Recall the general formula for alkynes, , where the first member starts with (ethyne).
Quick Oral Answer
The first member of the alkyne series is ethyne (). The subsequent members are propyne () and butyne (), which differ by successive units.
Analysis & Explanation
The homologous series of alkynes has the general formula .
- The first member of this series is ethyne (), where .
- The second member is propyne (), where .
- The third member is butyne (), where .
Common Mistakes
- 1Writing as the second member by assuming is possible for alkynes.
- 2Confusing alkynes with alkenes () or alkanes ().
Interesting Facts
Alkynes contain at least one carbon-carbon triple bond. Because a triple bond requires two carbon atoms, the simplest alkyne (ethyne) must have at least two carbon atoms, meaning there is no single-carbon alkyne.
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Frequently Asked Questions
How many marks does this question carry in CBSE Class 10 Science 2017?
This question carries 1 mark in the CBSE Class 10 Science 2017 examination.
Which chapter does this question come from in Science?
This question is from the chapter "Carbon and its Compounds" in the CBSE Class 10 Science syllabus.
What topic does this question cover in Science?
This question covers the topic "Homologous Series" from CBSE Class 10 Science.
What type of question is this in the CBSE Class 10 Science 2017 paper?
This is a Very Short Answer question from Section A in the CBSE Class 10 Science 2017 paper.