Q28
1 markMCQSection B

In your laboratory you trace the path of light rays through a glass slab for different values of angle of incidence (∠i) and in each case measure the values of the corresponding angle of refraction (∠r) and angle of emergence (∠e). On the basis of your observations your correct conclusion is :

Also asked in:2016
Light — Reflection and Refraction
Refraction through a rectangular glass slab

Options

(a)∠i is more than ∠r, but nearly equal to ∠e
(b)∠i is less than ∠r, but nearly equal to ∠e
(c)∠i is more than ∠e, but nearly equal to ∠r
(d)∠i is less than ∠e, but nearly equal to ∠r
Official Answer

The correct conclusion is that the angle of incidence (i\angle i) is more than the angle of refraction (r\angle r), but nearly equal to the angle of emergence (e\angle e). Hence, option (a) is correct.

angle of incidenceangle of refractionangle of emergenceparalleltowards the normal

Marking Scheme

  • 11 mark for selecting the correct option (a) with correct reasoning.

Hint

Recall that light bends towards the normal when entering a denser medium, and the emergent ray is parallel to the incident ray for a parallel-sided glass slab.

Quick Oral Answer

When light passes through a rectangular glass slab, the angle of incidence is equal to the angle of emergence because the opposite refracting faces of the slab are parallel, causing equal and opposite bending at the two interfaces.

Analysis & Explanation

When a ray of light enters from air (an optically rarer medium) to glass (an optically denser medium), it bends towards the normal. Therefore, the angle of refraction (r\angle r) is less than the angle of incidence (i\angle i), which means i>r\angle i > \angle r.


When the light ray emerges from the opposite parallel face of the rectangular glass slab into air, it bends away from the normal. Since the two refracting surfaces are parallel, the emergent ray is parallel to the incident ray, meaning the angle of emergence (e\angle e) is equal to the angle of incidence (i\angle i), i.e., ie\angle i \approx \angle e.


  • Option (a) is correct because it accurately states that i>r\angle i > \angle r and ie\angle i \approx \angle e.
  • Option (b) is incorrect because i\angle i is greater than r\angle r, not less.
  • Option (c) is incorrect because i\angle i is nearly equal to e\angle e, not greater, and i\angle i is not equal to r\angle r.
  • Option (d) is incorrect because i\angle i is nearly equal to e\angle e, not less, and i\angle i is not equal to r\angle r.

Common Mistakes

  1. 1Students often confuse the angle of refraction with the angle of emergence, or incorrectly assume that the light bends away from the normal when entering glass.

Interesting Facts

The emergent ray is laterally shifted (displaced) relative to the incident ray. This perpendicular distance between the original incident path and the emergent ray is known as lateral displacement, which increases with the thickness and refractive index of the glass slab.

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Frequently Asked Questions

How many marks does this question carry in CBSE Class 10 Science 2016?

This question carries 1 mark in the CBSE Class 10 Science 2016 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Light — Reflection and Refraction" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Refraction through a rectangular glass slab" from CBSE Class 10 Science.

Has this question appeared in other CBSE Science papers?

Yes, a similar question appeared in the 2016 CBSE Class 10 Science paper.

What type of question is this in the CBSE Class 10 Science 2016 paper?

This is a MCQ question from Section B in the CBSE Class 10 Science 2016 paper.