Q31
1 markMCQSection B

A student obtained a sharp image of a burning candle, placed at the farther end of a laboratory table, on a screen using a concave mirror. For getting better value of focal length of the mirror, the subject teacher suggested him for focussing a well illuminated distant object. What should the student do?

Light — Reflection and Refraction
Focal Length of a Concave Mirror

Options

(A)He should move the mirror away from the screen.
(B)He should move the mirror slightly towards the screen.
(C)He should move the mirror as well as the screen towards the newly selected object.
(D)He should move only the screen towards the newly selected object.
Official Answer

The correct option is B. He should move the mirror slightly towards the screen.

concave mirrordistant objectfocusimage distancedecrease distance

Marking Scheme

  • 1Explaining that the image of a distant object forms closer to the mirror (at the focus) than a nearby object (0.5 marks)
  • 2Concluding that the distance between the mirror and screen must be decreased, hence moving the mirror towards the screen (0.5 marks)

Hint

As an object moves further away from a concave mirror (towards infinity), its image moves closer to the mirror (towards the focus). Think about how the distance between the mirror and screen must change.

Quick Oral Answer

Q: What is the nature of the image formed by a concave mirror when the object is at infinity? A: The image is real, inverted, highly diminished (point-sized), and formed at the principal focus of the mirror.

Analysis & Explanation

Let us analyze the position of the image in both scenarios:

  1. Initial Scenario (Candle at the end of the table):
  • The candle is at a finite distance (uu) from the concave mirror.
  • Since the object is at a finite distance beyond the focus, its real image is formed at a distance vv which is greater than the focal length (v>fv > f).
  • The screen is placed at this distance vv to capture the sharp image.

  1. New Scenario (Distant Object):
  • A well-illuminated distant object is at infinity (uu \approx \infty).
  • The parallel rays from this distant object converge exactly at the principal focus of the concave mirror (v=fv = f).

Since f<vf < v, the distance between the mirror and the screen must be decreased to obtain a sharp image of the distant object.

  • To decrease this distance, the student should move the mirror slightly towards the screen (or move the screen slightly towards the mirror).
  • Therefore, Option B is the correct action.

Why other options are incorrect:

  • Option A: Moving the mirror away from the screen increases the distance between them, which would make the image highly blurred.
  • Option C: Moving both towards the object does not systematically address the relative distance reduction needed between the mirror and the screen.
  • Option D: Moving only the screen towards the newly selected object (which is far away) would increase the mirror-screen distance, which is incorrect.

Common Mistakes

  1. 1Students often think that moving the mirror towards the object is required, forgetting that the relative distance between the mirror and the screen is what determines image sharpness.
  2. 2Misunderstanding the mirror formula 1f=1v+1u\frac{1}{f} = \frac{1}{v} + \frac{1}{u} and how vv changes as uu increases.

Interesting Facts

Concave mirrors are used in solar furnaces to focus sunlight (rays from a distant source) at a single point to generate extreme heat.

Spotted a mistake or something unclear?

Tell us — we fix reported answers fast.

Frequently Asked Questions

How many marks does this question carry in CBSE Class 10 Science 2013?

This question carries 1 mark in the CBSE Class 10 Science 2013 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Light — Reflection and Refraction" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Focal Length of a Concave Mirror" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2013 paper?

This is a MCQ question from Section B in the CBSE Class 10 Science 2013 paper.