Q5
2 marksShort AnswerSection A

Choose from the following :

6C,8O,10Ne,11Na,14Si6C, 8O, 10Ne, 11Na, 14Si

(i) Elements that should be in the same period.

(ii) Elements that should be in the same group.

State reason for your selection in each case.

Metals and Non-metals
Classification of Elements and Electronic Configuration
Official Answer

(i) Elements in the same period:

  • Set 1: 6C_{6}\text{C}, 8O_{8}\text{O}, and 10Ne_{10}\text{Ne} belong to the same period (Period 2).
  • Reason: Their electronic configurations are 6C=2,4_{6}\text{C} = 2, 4, 8O=2,6_{8}\text{O} = 2, 6, and 10Ne=2,8_{10}\text{Ne} = 2, 8. All three elements have electrons distributed in exactly two shells (KK and LL). Since the number of occupied shells determines the period number, they belong to the same period.
  • Set 2: 11Na_{11}\text{Na} and 14Si_{14}\text{Si} belong to the same period (Period 3).
  • Reason: Their electronic configurations are 11Na=2,8,1_{11}\text{Na} = 2, 8, 1 and 14Si=2,8,4_{14}\text{Si} = 2, 8, 4. Both elements have electrons distributed in three shells (KK, LL, and MM).

(ii) Elements in the same group:

  • Elements: 6C_{6}\text{C} and 14Si_{14}\text{Si} belong to the same group (Group 14).
  • Reason: Their electronic configurations are 6C=2,4_{6}\text{C} = 2, 4 and 14Si=2,8,4_{14}\text{Si} = 2, 8, 4. Both elements have the same number of valence electrons (4 electrons in their outermost shell). Since elements with the same number of valence electrons are placed in the same group, they belong to the same group.
same periodsame number of shellssame groupsame valence electronselectronic configuration

Marking Scheme

  • 11 mark
  • 21 mark

Hint

Write the electronic configuration of each element. The number of shells determines the period, and the number of valence electrons determines the group.

Quick Oral Answer

Elements with the same number of electron shells are placed in the same period, while elements with the same number of valence electrons are placed in the same group.

Analysis & Explanation

The periodic table organizes elements such that the period number corresponds to the number of electron shells, and the group number corresponds to the number of valence electrons (for main group elements, Group Number = Valence Electrons for 1-2, and 10+Valence Electrons10 + \text{Valence Electrons} for 13-18). By writing down the electronic configurations of 6C_{6}\text{C} (2,42, 4), 8O_{8}\text{O} (2,62, 6), 10Ne_{10}\text{Ne} (2,82, 8), 11Na_{11}\text{Na} (2,8,12, 8, 1), and 14Si_{14}\text{Si} (2,8,42, 8, 4), we can easily group them based on these rules.

Common Mistakes

  1. 1Confusing period number with valence electrons and group number with the number of shells.
  2. 2Writing incorrect electronic configurations, especially for sodium or silicon.

Interesting Facts

Carbon and Silicon both belong to Group 14 (the carbon family) and are capable of forming covalent bonds, though carbon forms much stronger catenated chains than silicon.

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Frequently Asked Questions

How many marks does this question carry in CBSE Class 10 Science 2012?

This question carries 2 marks in the CBSE Class 10 Science 2012 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Metals and Non-metals" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Classification of Elements and Electronic Configuration" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2012 paper?

This is a Short Answer question from Section A in the CBSE Class 10 Science 2012 paper.