Q30
1 markMCQSection B

Rahim recorded the following sets of observations while tracing the path of a ray of light passing through a rectangular glass slab for different angles of incidence.


S. No.Angle of incidenceAngle of refractionAngle of emergenceI454145II403838III454140IV414541\begin{array}{|c|c|c|c|} \hline \text{S. No.} & \text{Angle of incidence} & \text{Angle of refraction} & \text{Angle of emergence} \\ \hline \text{I} & 45^\circ & 41^\circ & 45^\circ \\ \hline \text{II} & 40^\circ & 38^\circ & 38^\circ \\ \hline \text{III} & 45^\circ & 41^\circ & 40^\circ \\ \hline \text{IV} & 41^\circ & 45^\circ & 41^\circ \\ \hline \end{array}


The correct observation is recorded at serial number:

Light — Reflection and Refraction
Refraction of Light through a Glass Slab

Options

(1)I
(2)II
(3)III
(4)IV
Official Answer

The correct observation is recorded at serial number I, which corresponds to option 1.

angle of incidenceangle of refractionangle of emergenceequalless than

Marking Scheme

  • 11 mark for identifying the correct observation (I) based on the conditions r<ir < i and e=ie = i.

Hint

For a rectangular glass slab, the angle of refraction must be less than the angle of incidence (r<ir < i), and the angle of emergence must be equal to the angle of incidence (e=ie = i).

Quick Oral Answer

In a rectangular glass slab, the angle of incidence (ii) is always equal to the angle of emergence (ee) because the two refracting surfaces are parallel to each other.

Analysis & Explanation

For a rectangular glass slab, the light ray enters from air (refractive index nair1.0n_{\text{air}} \approx 1.0) to glass (refractive index nglass1.5n_{\text{glass}} \approx 1.5).


  1. Bending towards the normal: Since glass is optically denser than air, the light ray bends towards the normal upon entry. This means the angle of refraction (rr) must be strictly less than the angle of incidence (ii):

r<ir < i

  1. Parallel Emergence: Since the opposite refracting faces of the rectangular glass slab are parallel, the emergent ray is parallel to the incident ray. This means the angle of emergence (ee) must be equal to the angle of incidence (ii):

e=ie = i


Let us evaluate the given observations:

  • Observation I: i=45i = 45^\circ, r=41r = 41^\circ, e=45e = 45^\circ. Here, r<ir < i (41<4541^\circ < 45^\circ) and e=ie = i (45=4545^\circ = 45^\circ). This observation is correct.
  • Observation II: i=40i = 40^\circ, r=38r = 38^\circ, e=38e = 38^\circ. Here, eie \neq i (384038^\circ \neq 40^\circ), which is incorrect.
  • Observation III: i=45i = 45^\circ, r=41r = 41^\circ, e=40e = 40^\circ. Here, eie \neq i (404540^\circ \neq 45^\circ), which is incorrect.
  • Observation IV: i=41i = 41^\circ, r=45r = 45^\circ, e=41e = 41^\circ. Here, r>ir > i (45>4145^\circ > 41^\circ), which implies the ray bent away from the normal when entering a denser medium. This is physically incorrect.

Common Mistakes

  1. 1Choosing an option where the angle of emergence is not equal to the angle of incidence, or where the angle of refraction is greater than the angle of incidence when entering glass.

Interesting Facts

Even though the emergent ray is parallel to the incident ray, it is shifted sideways. This perpendicular distance between the original path of the incident ray and the emergent ray is called lateral shift.

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Frequently Asked Questions

How many marks does this question carry in CBSE Class 10 Science 2011?

This question carries 1 mark in the CBSE Class 10 Science 2011 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Light — Reflection and Refraction" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Refraction of Light through a Glass Slab" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2011 paper?

This is a MCQ question from Section B in the CBSE Class 10 Science 2011 paper.