(A) (i) State the rule which gives the direction of force acting on the current carrying conductor placed in a uniform magnetic field.

(ii) Name any two devices which work on the basis of an interaction between magnetic field and current carrying conductor.

(iii) Comment on the magnitude of force on electron in both the cases and give reason for your answer.

OR

(B) (i) List three possible reasons of short-circuiting in an electric circuit.

(ii) In case of overload, will the fuse protect to given electric circuit from damage? Justify your answer.

(iii) For an electric heater rated as 220 V, 2200 W, what should be the minimum rating of fuse used with it?

(A) (i) The direction of force acting on the current carrying conductor placed in a uniform magnetic field is given by Fleming’s left hand rule.

(ii) Two devices which work on the basis of an interaction between magnetic field and current carrying conductor are:

1. Electric motor
2. Galvanometer

(iii) The magnitude of force on electron in both the cases is same because the force acting on a current carrying conductor placed in a uniform magnetic field is independent of the type of charge carrier.

OR

(B) (i) Three possible reasons of short-circuiting in an electric circuit are:

1. Overloading
2. Poor insulation of wires
3. Faulty appliances

(ii) Yes, the fuse will protect the given electric circuit from damage in case of overload. This is because the fuse wire has a low melting point and it melts when the current exceeds a certain limit, thus breaking the circuit.

(iii) The minimum rating of fuse used with an electric heater rated as 220 V, 2200 W should be 10 A.