An electric bulb is rated . The resistance of its filament when it glows with a power supply of is :
An electric bulb is rated . The resistance of its filament when it glows with a power supply of is :
Options
Official answer
The resistance of the filament can be calculated using the formula R = V^2/P, where V is the voltage and P is the power. Substituting the values, we get R = (220 V)^2 / 11 W = 4400 ohms.
Marking scheme
- 1.1 mark for correct answer
Hint
Use the formula R = V^2/P to calculate the resistance.
Quick oral answer
The resistance of the filament is 4400 ohms.
Common mistakes
- 1.Incorrect calculation of resistance
Analysis and explanation
This problem requires the application of the formula R = V^2/P to calculate the resistance of the filament. The correct answer is 4400 ohms.
Interesting facts
The concept of resistance is important in electrical engineering and electronics.
Question details
Q13 of 39 questions
- Board
- CBSE
- Class
- Class 10
- Subject
- Science
- Year
- 2025
- Section
- Section A
- Marks
- 1
- Type
- MCQ
- Chapter
- Electricity
- Topic
- Electricity
- Bloom's level
- Remembering
- Syllabus topic
- Electricity
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Frequently asked questions
How many marks does this question carry in CBSE Class 10 Science 2025?
This question carries 1 mark in the CBSE Class 10 Science 2025 examination.
Which chapter does this question come from in Science?
This question is from the chapter "Electricity" in the CBSE Class 10 Science syllabus.
What topic does this question cover in Science?
This question covers the topic "Electricity" from CBSE Class 10 Science.
What type of question is this in the CBSE Class 10 Science 2025 paper?
This is a MCQ question from Section A in the CBSE Class 10 Science 2025 paper.