In a domestic circuit five LED bulbs are arranged as shown. The source voltage is 220 V and the power rating of each bulb is marked in the circuit diagram. Based on the following circuit diagram, answer the following questions: (a) State what happens when (i) key $K_1$ is closed. (ii) key $K_2$ is closed. (b) Find the current drawn by the bulb B when it glows. (c) Calculate (i) the resistance of bulb B, and (ii) total resistance of the combination of four bulbs B, C, D and E. OR (c) What would happen to the glow of all the bulbs in the circuit when keys $K_1$ and $K_2$ both are closed and the bulb C suddenly get fused? Give reason to justify your answer.

The given circuit diagram shows five LED bulbs arranged in a specific configuration. The source voltage is 220 V, and the power rating of each bulb is marked in the circuit diagram. To answer the questions, we need to analyze the circuit and apply the principles of electric circuits. (a) State what happens when (i) key $K_1$ is closed. (ii) key $K_2$ is closed. When key $K_1$ is closed, the circuit is completed, and the bulbs will glow. The current will flow through the bulbs, and they will emit light. When key $K_2$ is closed, the circuit is also completed, and the bulbs will glow. However, the current will flow through the bulbs in a different path, and the brightness of the bulbs may vary. (b) Find the current drawn by the bulb B when it glows. To find the current drawn by bulb B, we need to calculate the total resistance of the circuit and then use Ohm's law to find the current. The total resistance of the circuit can be calculated by adding the resistances of all the bulbs in series. Let's assume the resistance of each bulb is $R$. The total resistance of the circuit is $5R$. Using Ohm's law, we can calculate the current drawn by bulb B: I = rac{V}{R} = rac{220}{5R} = rac{44}{R} (c) Calculate (i) the resistance of bulb B, and (ii) total resistance of the combination of four bulbs B, C, D, and E. (i) The resistance of bulb B can be calculated using the power rating of the bulb. The power rating of bulb B is 11 W, and the voltage is 220 V. Using the formula P = rac{V^2}{R}, we can calculate the resistance of bulb B: R = rac{V^2}{P} = rac{(220)^2}{11} = 484 ext{ ohms} (ii) The total resistance of the combination of four bulbs B, C, D, and E can be calculated by adding the resistances of all the bulbs in series. Let's assume the resistance of each bulb is $R$. The total resistance of the circuit is $4R$. Using Ohm's law, we can calculate the total resistance of the combination of four bulbs: $R_{total} = 4R = 4 imes 484 = 1936 ext{ ohms}$ OR (c) What would happen to the glow of all the bulbs in the circuit when keys $K_1$ and $K_2$ both are closed and the bulb C suddenly gets fused? Give reason to justify your answer. When keys $K_1$ and $K_2$ both are closed, the circuit is completed, and the bulbs will glow. If bulb C suddenly gets fused, the circuit will be broken, and the current will not flow through the bulbs. As a result, all the bulbs will stop glowing. This is because the circuit is no longer complete, and there is no path for the current to flow. Therefore, the glow of all the bulbs in the circuit will be affected when bulb C gets fused. stepByStepSolution: [ {