(a) A neutral organic compound (Molecular formula ) on reacting with acidified gives an organic compound which is acidic in nature. reacts with on warming in the presence of conc. to give a sweet smelling compound . (i) Identify , and . (ii) Write the chemical equations for the reactions in the conversion of (1) to and (2) to . (iii) State the role of (1) acidified in the conversion of to and (2) conc. in the reaction of and . (iv) Name the reaction which occurs when reacts with an alkali. OR (b) Carry out the following conversions, stating the condition(s) for each : (i) Ethanol Ethene (ii) Ethene Ethane (iii) Ethane Chloroethane (iv) Ethanol Ethanoic acid (v) Ethanoic acid Ethyl ethanoate
(a) A neutral organic compound (Molecular formula ) on reacting with acidified gives an organic compound which is acidic in nature. reacts with on warming in the presence of conc. to give a sweet smelling compound . (i) Identify , and . (ii) Write the chemical equations for the reactions in the conversion of (1) to and (2) to . (iii) State the role of (1) acidified in the conversion of to and (2) conc. in the reaction of and . (iv) Name the reaction which occurs when reacts with an alkali. OR (b) Carry out the following conversions, stating the condition(s) for each : (i) Ethanol Ethene (ii) Ethene Ethane (iii) Ethane Chloroethane (iv) Ethanol Ethanoic acid (v) Ethanoic acid Ethyl ethanoate
Part (a)
(i) Identification:
- is Ethanol ( or ).
- is Ethanoic acid ().
- is Ethyl ethanoate (), which is a sweet-smelling ester.
(ii) Chemical Equations:
- Conversion of to (Oxidation):
- Conversion of and to (Esterification):
(iii) Role of Reagents:
- Acidified : It acts as an oxidizing agent that provides nascent oxygen to oxidize ethanol to ethanoic acid.
- Concentrated : It acts as a catalyst to speed up the reaction and as a dehydrating agent to remove the water formed, shifting the equilibrium in the forward direction to maximize the yield of ester.
(iv) Name of the reaction:
When ester reacts with an alkali, the reaction is called Saponification (alkaline hydrolysis of an ester).
Part (b) (OR Part)
(i) Ethanol to Ethene:
- Condition: Heating ethanol at with excess concentrated .
- Equation:
(ii) Ethene to Ethane:
- Condition: Heating ethene with hydrogen gas in the presence of a nickel () or palladium () catalyst.
- Equation:
(iii) Ethane to Chloroethane:
- Condition: Reaction of ethane with chlorine gas in the presence of sunlight.
- Equation:
(iv) Ethanol to Ethanoic acid:
- Condition: Heating ethanol with alkaline potassium permanganate () or acidified potassium dichromate ().
- Equation:
(v) Ethanoic acid to Ethyl ethanoate:
- Condition: Warming ethanoic acid with ethanol in the presence of a few drops of concentrated sulphuric acid.
- Equation:
Marking Scheme
- 1Part (a):
- 2- 1.5 marks for identifying X', Y', and Z' (0.5 mark each).
- 3- 1.5 marks for writing both chemical equations correctly (0.75 mark each).
- 4- 1 mark for stating the roles of acidified potassium dichromate and concentrated sulphuric acid (0.5 mark each).
- 5- 1 mark for naming the saponification reaction.
- 6OR Part (b):
- 7- 1 mark for each correct conversion with appropriate conditions and chemical equations (5 x 1 = 5 marks).
Hint
- For , think of a common 2-carbon alcohol. - Acidified is a powerful oxidizing agent. - Sweet-smelling compounds are always esters. - Remember that dehydration of ethanol requires a specific temperature of with concentrated .
Quick Oral Answer
Ethanol can be converted to ethanoic acid by heating it with an oxidizing agent like acidified potassium dichromate. When these two compounds react together in the presence of concentrated sulphuric acid, they form a sweet-smelling ester called ethyl ethanoate.
Analysis & Explanation
This question tests the student's comprehensive understanding of the chemical properties of carbon compounds, specifically focusing on ethanol and ethanoic acid.
- Oxidation: Alcohols are oxidized to carboxylic acids using strong oxidizing agents. Acidified potassium dichromate () is a classic reagent for this conversion.
- Esterification: Carboxylic acids react with alcohols in an acidic medium to form esters. This is a reversible reaction, which is why a dehydrating agent like concentrated is crucial to drive the reaction forward by removing water.
- Saponification: Esters are cleaved by strong bases (alkalis) to regenerate the alcohol and form the sodium/potassium salt of the carboxylic acid. This reaction is the basis of soap-making.
- Dehydration: Concentrated sulphuric acid acts as a strong dehydrating agent at high temperatures (), converting ethanol to ethene.
- Addition Reaction: Unsaturated hydrocarbons (alkenes) undergo addition reactions with hydrogen in the presence of catalysts like nickel to form saturated hydrocarbons (alkanes).
- Substitution Reaction: Saturated hydrocarbons (alkanes) are relatively unreactive but undergo substitution reactions with halogens in the presence of sunlight.
Common Mistakes
- 1Writing the incorrect temperature for the dehydration of ethanol (using temperatures other than can yield ether instead of ethene).
- 2Forgetting to write the reaction conditions (like sunlight, catalysts, or heat) over the reaction arrows.
- 3Confusing the formulas of ethane (), ethene (), and ethyne ().
Interesting Facts
Esterification is a reversible reaction, and the sweet smell of esters is what gives many fruits, like bananas and pineapples, their characteristic aromas.
Saponification literally means 'soap-making' because the sodium salts of long-chain carboxylic acids formed in this reaction are the primary components of household soaps.
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Frequently Asked Questions
How many marks does this question carry in CBSE Class 10 Science 2023?
This question carries 5 marks in the CBSE Class 10 Science 2023 examination.
Which chapter does this question come from in Science?
This question is from the chapter "Carbon and its Compounds" in the CBSE Class 10 Science syllabus.
What topic does this question cover in Science?
This question covers the topic "Chemical Properties of Carbon Compounds" from CBSE Class 10 Science.
What type of question is this in the CBSE Class 10 Science 2023 paper?
This is a Long Answer question from Section D in the CBSE Class 10 Science 2023 paper.