Two LED bulbs of $12W$ and $6W$ are connected in series. If the current through $12W$ bulb is $0.06A$ the current through $6W$ bulb will be :

In a series circuit, there is only a single path for the flow of electric charge. Consequently, the electric current ($I$) remains identical through all components connected in series. Since the $12\text{ W}$ LED bulb and the $6\text{ W}$ LED bulb are connected in series, the current flowing through the $6\text{ W}$ bulb must be exactly equal to the current flowing through the $12\text{ W}$ bulb, which is $0.06\text{ A}$.

• Why other options are incorrect:
• Option (a) $0.04\text{ A}$, Option (c) $0.08\text{ A}$, and Option (d) $0.12\text{ A}$ are incorrect because they assume that current divides or changes across components in a series circuit, which violates the law of conservation of charge in a single-loop circuit.