In a resistive circuit if the current is increased to two times, the percentage change in the amount of heat dissipated in the circuit would be :

The heat dissipated in a resistive circuit is given by the formula $H = I^2Rt$, where $I$ is the current, $R$ is the resistance, and $t$ is the time. If the current is increased to two times, the heat dissipated becomes $H' = (2I)^2Rt = 4I^2Rt$. The percentage change in the amount of heat dissipated is given by rac{H' - H}{H} imes 100\% = rac{4I^2Rt - I^2Rt}{I^2Rt} imes 100\% = 300\%. Therefore, the percentage change in the amount of heat dissipated in the circuit would be $400\%$.