Study the following electric circuit in which the resistors are arranged in three arms A, B and C:

(a) Find the equivalent resistance of arm A. (1 mark)

(b) Calculate the equivalent resistance of the parallel combination of the arms B and C. (1 mark)

(c) (i) Determine the current that flows through the ammeter. (2 marks)

OR

(ii) Determine the current that flows in the ammeter when the arm B is withdrawn from the circuit. (2 marks)

To solve this problem, we need to apply the concepts of electric circuits and resistance. First, let's analyze the circuit and identify the resistors in each arm. Arm A has two resistors in series, so we can calculate the equivalent resistance using the formula Req = R1 + R2. Arm B has two resistors in parallel, so we can calculate the equivalent resistance using the formula 1/Req = 1/R1 + 1/R2. Arm C has one resistor. Once we have the equivalent resistances for each arm, we can calculate the total resistance of the circuit using the formula Rtotal = RA + RB + RC. Finally, we can use Ohm's law to calculate the current flowing through the ammeter. However, since the question does not provide specific values for the resistors, we cannot perform the calculations. Therefore, the answer is not applicable.