Question 173 marksShort AnswerSection B

From the elements 1939A^{39}_{19}\mathrm{A}, 1428B^{28}_{14}\mathrm{B}, 816C^{16}_{8}\mathrm{C} and 1840D^{40}_{18}\mathrm{D} identify: (a) the most electro positive element. (b) a noble gas. (c) a metalloid. (d) an element which will gain 2 electrons to attain nearest noble gas configuration. (e) formula of compound formed between A and C. (f) elements belonging to same period.

Metals and Non-metals
Chemical Properties of Metals

Official answer

Based on the atomic numbers (subscripts) of the given elements, we first identify their electronic configurations:

  • 1939A^{39}_{19}\text{A}: Atomic number Z=19Z = 19. Electronic configuration = 2,8,8,12, 8, 8, 1 (Potassium, K\text{K})
  • 1428B^{28}_{14}\text{B}: Atomic number Z=14Z = 14. Electronic configuration = 2,8,42, 8, 4 (Silicon, Si\text{Si})
  • 816C^{16}_{8}\text{C}: Atomic number Z=8Z = 8. Electronic configuration = 2,62, 6 (Oxygen, O\text{O})
  • 1840D^{40}_{18}\text{D}: Atomic number Z=18Z = 18. Electronic configuration = 2,8,82, 8, 8 (Argon, \text{Ar})

(a) The most electropositive element:

A\text{A} (1939A^{39}_{19}\text{A}) is the most electropositive element because it has only 11 valence electron in its outermost shell, which it can lose very easily to attain a stable octet.


(b) A noble gas:

D\text{D} (1840D^{40}_{18}\text{D}) is a noble gas because its outermost shell is completely filled (octet configuration: 2,8,82, 8, 8).


(c) A metalloid:

B\text{B} (1428B^{28}_{14}\text{B}) is a metalloid (Silicon) because it has 44 valence electrons and exhibits properties intermediate between metals and non-metals.


(d) Element which will gain 2 electrons to attain nearest noble gas configuration:

C\text{C} (816C^{16}_{8}\text{C}) has 66 valence electrons (2,62, 6). It needs 22 more electrons to complete its octet and attain the stable configuration of Neon (2,82, 8).


(e) Formula of compound formed between A and C:

  • Element A\text{A} has a valency of +1+1 (loses 11 electron: A+\text{A}^+).
  • Element C\text{C} has a valency of −2-2 (gains 22 electrons: C2−\text{C}^{2-}).
  • By criss-cross method, the chemical formula is A2C\text{A}_2\text{C} (which represents Potassium Oxide, K2O\text{K}_2\text{O}).

(f) Elements belonging to the same period:

B\text{B} and D\text{D} belong to the same period (Period 3) because both have electrons distributed across three shells (KK, LL, and MM).

Answer keywords:electropositivenoble gasmetalloidvalence electronsoctetA2Csame period

Marking scheme

  1. 1.0.5 marks for identifying A as the most electropositive element.
  2. 2.0.5 marks for identifying D as the noble gas.
  3. 3.0.5 marks for identifying B as the metalloid.
  4. 4.0.5 marks for identifying C as the element that gains 2 electrons.
  5. 5.0.5 marks for writing the correct formula A2C.
  6. 6.0.5 marks for identifying B and D as belonging to the same period.

Hint

First write down the electronic configuration of each element using their atomic numbers (the lower numbers). The number of shells tells you the period, and the valence electrons tell you the chemical behavior.

Quick oral answer

The period of an element in the periodic table is determined by the total number of electron shells it possesses. For example, Silicon and Argon both have 3 shells, so they belong to Period 3.

Common mistakes

  1. 1.Using the mass number (superscript) instead of the atomic number (subscript) to write electronic configurations.
  2. 2.Writing the formula as AC2 instead of A2C due to incorrect valency assignment.

Analysis and explanation

This question tests the student's ability to decode the symbolic representation of elements (ZAX^{A}_{Z}\text{X} where ZZ is the atomic number and AA is the mass number). By writing down the electronic configurations, students can deduce chemical properties such as valency, metallic/non-metallic character, period number, and chemical formula formation. This bridges the concepts of atomic structure with chemical reactivity in Chapter 3.

Interesting facts

Element A is Potassium, which is so reactive that it reacts violently with cold water and must be stored under kerosene oil to prevent it from catching fire spontaneously in air!

Question details

Q17 of 45 questions

Board
CBSE
Class
Class 10
Subject
Science
Year
2020
Section
Section B
Marks
3
Type
Short Answer
Chapter
Metals and Non-metals
Topic
Chemical Properties of Metals
Bloom's level
Analyzing
Syllabus topic
Electronic configuration, reactivity, and periodic properties of elements

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Frequently asked questions

How many marks does this question carry in CBSE Class 10 Science 2020?

This question carries 3 marks in the CBSE Class 10 Science 2020 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Metals and Non-metals" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Chemical Properties of Metals" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2020 paper?

This is a Short Answer question from Section B in the CBSE Class 10 Science 2020 paper.