Q7
3 marksShort AnswerSection A

On dropping a small piece of sodium in a test tube containing carbon compound ‘X’ with molecular formula C2H6OC_2H_6O, a brisk effervescence is observed and a gas ‘Y’ is produced. On bringing a burning splinter at the mouth of the test tube the gas evolved burns with a pop sound. Identify ‘X’ and ‘Y’. Also write the chemical equation for the reaction. Write the name and structure of the product formed, when you heat ‘X’ with excess conc. sulphuric acid.

Carbon and its Compounds
Chemical Properties of Carbon Compounds
Official Answer
  1. Identification of X and Y:
  • Compound X is ethanol (C2H6OC_2H_6O or CH3CH2OHCH_3CH_2OH).
  • Gas Y is hydrogen gas (H2H_2).

  1. Chemical Equation for the reaction of X with sodium:

2CH3CH2OH+2Na2CH3CH2ONa+H22CH_3CH_2OH + 2Na \rightarrow 2CH_3CH_2ONa + H_2 \uparrow

(The ionic product formed is sodium ethoxide)


  1. Reaction of X with excess concentrated sulphuric acid:

When ethanol (X) is heated with excess concentrated H2SO4H_2SO_4 at 443 K443\text{ K}, it undergoes dehydration to form ethene.

  • Name of the product: Ethene
  • Structure of the product:

``

H H

\ /

C = C

/ \

H H

``

  • Chemical Equation:

CH3CH2OHHot conc. H2SO4CH2=CH2+H2OCH_3CH_2OH \xrightarrow{\text{Hot conc. } H_2SO_4} CH_2=CH_2 + H_2O

ethanolhydrogensodium ethoxideethenedehydrationconcentrated sulphuric acid

Marking Scheme

  • 1Identification of X as ethanol and Y as hydrogen gas (1 mark)
  • 2Balanced chemical equation for the reaction of ethanol with sodium (1 mark)
  • 3Name (ethene) and correct structural formula of the dehydration product (1 mark)

Hint

Compound X is a two-carbon alcohol that reacts with sodium to release a gas that burns with a pop sound. Heating this alcohol with a strong dehydrating agent like conc. H2SO4H_2SO_4 removes water to form an alkene.

Quick Oral Answer

Compound X is ethanol and gas Y is hydrogen. When ethanol is heated with excess concentrated sulphuric acid, it gets dehydrated to form ethene, which contains a double bond.

Analysis & Explanation

Ethanol reacts with active metals like sodium to form sodium ethoxide and hydrogen gas. Concentrated sulphuric acid acts as a strong dehydrating agent at high temperatures (443 K443\text{ K}), removing the OH-OH group from one carbon and a hydrogen atom from the adjacent carbon to establish a carbon-carbon double bond, yielding ethene.

Common Mistakes

  1. 1Writing the formula of the gas as HH instead of H2H_2.
  2. 2Confusing the dehydration product with ethane (C2H6C_2H_6) instead of ethene (C2H4C_2H_4).
  3. 3Not mentioning the reaction conditions like heating with concentrated H2SO4H_2SO_4.

Interesting Facts

Concentrated sulphuric acid is so hungry for water (hygroscopic) that it can chemically strip hydrogen and oxygen atoms from organic molecules to form water, leaving behind carbon or unsaturated compounds.

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Frequently Asked Questions

How many marks does this question carry in CBSE Class 10 Science 2016?

This question carries 3 marks in the CBSE Class 10 Science 2016 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Carbon and its Compounds" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Chemical Properties of Carbon Compounds" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2016 paper?

This is a Short Answer question from Section A in the CBSE Class 10 Science 2016 paper.