Q32
1 markMCQSection B

In your laboratory you trace the path of light rays through a glass slab for different values of angle of incidence (i\angle i) and in each case measure the values of the corresponding angle of refraction (r\angle r) and angle of emergence (e\angle e). On the basis of your observations your correct conclusion is:

Light — Reflection and Refraction
Refraction through a rectangular glass slab

Options

(a)i\angle i is more than r\angle r, but nearly equal to e\angle e
(b)i\angle i is less than r\angle r, but nearly equal to e\angle e
(c)i\angle i is more than e\angle e, but nearly equal to r\angle r
(d)i\angle i is less than e\angle e, but nearly equal to r\angle r
Official Answer

The correct option is a.

angle of incidenceangle of refractionangle of emergenceparalleltowards the normalrarer to denser

Marking Scheme

  • 11 Mark for selecting the correct option (a) with the correct relation between the angles.

Hint

Remember that light bends towards the normal when entering a denser medium like glass, and the emergent ray is parallel to the incident ray.

Quick Oral Answer

When light passes through a glass slab, the angle of incidence is greater than the angle of refraction because glass is optically denser than air. The angle of incidence is equal to the angle of emergence because the two refracting faces of the slab are parallel to each other.

Analysis & Explanation

When a ray of light enters a rectangular glass slab from air (an optically rarer medium) to glass (an optically denser medium), it bends towards the normal. Therefore, the angle of incidence (i\angle i) is greater than the angle of refraction (r\angle r), i.e., i>r\angle i > \angle r.


When the light ray emerges from the opposite parallel face of the glass slab back into the air, it bends away from the normal. Since the two refracting surfaces of the slab are parallel, the lateral bending at the second surface exactly compensates for the bending at the first surface. Thus, the emergent ray is parallel to the incident ray, which means the angle of emergence (e\angle e) is nearly equal to the angle of incidence (i\angle i).


  • Option a is correct because it accurately states i>r\angle i > \angle r and ie\angle i \approx \angle e.
  • Option b is incorrect because i\angle i is greater than r\angle r, not less.
  • Option c is incorrect because i\angle i is nearly equal to e\angle e, not greater than it.
  • Option d is incorrect because i\angle i is nearly equal to e\angle e and greater than r\angle r.

Common Mistakes

  1. 1Confusing the relationship between the angle of incidence and refraction, thinking light bends away from the normal when entering glass.
  2. 2Assuming the angle of emergence is equal to the angle of refraction.

Interesting Facts

The perpendicular distance between the original path of the incident ray and the emergent ray is called lateral displacement, which increases with the thickness of the glass slab.

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Frequently Asked Questions

How many marks does this question carry in CBSE Class 10 Science 2016?

This question carries 1 mark in the CBSE Class 10 Science 2016 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Light — Reflection and Refraction" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Refraction through a rectangular glass slab" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2016 paper?

This is a MCQ question from Section B in the CBSE Class 10 Science 2016 paper.