Question 321 markMCQSection B

Four students P, Q, R and S traced the path of a ray of light passing through a glass slab for an angle of incidence 40° and measured the angle of refraction. The values as measured them were 18°; 22°; 25° and 30° respectively. The student who has performed the experiment methodically is

Light — Reflection and Refraction
Refraction of Light

Options

(A)P
(B)Q
(C)R
(D)S

Official answer

The student who has performed the experiment methodically is R, who measured the angle of refraction as 25∘25^\circ.

Answer keywords:Snell's lawrefractive indexglass slabangle of refractionStudent R

Marking scheme

  1. 1.Correct option C selected (1 mark)

Hint

Use Snell's law sin⁡i/sin⁡r=n\sin i / \sin r = n with the refractive index of glass being approximately 1.51.5.

Quick oral answer

When a ray of light enters a glass slab from air, it bends towards the normal because glass is an optically denser medium than air.

Common mistakes

  1. 1.Assuming the angle of refraction is equal to the angle of incidence.
  2. 2.Not knowing the approximate refractive index of glass (1.51.5).

Analysis and explanation

According to Snell's law of refraction, the ratio of the sine of the angle of incidence (ii) to the sine of the angle of refraction (rr) is constant for a given pair of media, which is the refractive index (nn) of the second medium with respect to the first:

sin⁡isin⁡r=n\frac{\sin i}{\sin r} = n


For light travelling from air to glass, the refractive index of glass is approximately n≈1.5n \approx 1.5.

Given the angle of incidence i=40∘i = 40^\circ:

sin⁡(40∘)≈0.6428\sin(40^\circ) \approx 0.6428


Using Snell's law:

sin⁡r=sin⁡(40∘)1.5≈0.64281.5≈0.4285\sin r = \frac{\sin(40^\circ)}{1.5} \approx \frac{0.6428}{1.5} \approx 0.4285


Taking the inverse sine:

r=arcsin⁡(0.4285)≈25.37∘≈25∘r = \arcsin(0.4285) \approx 25.37^\circ \approx 25^\circ


Thus, the student who measured 25∘25^\circ (Student R) performed the experiment methodically and obtained the most accurate result.


  • Distractor A (Student P, 18∘18^\circ): This value is too low and would correspond to an unrealistically high refractive index of about 2.082.08.
  • Distractor B (Student Q, 22∘22^\circ): This value corresponds to a refractive index of about 1.721.72, which is higher than standard crown glass.
  • Distractor D (Student S, 30∘30^\circ): This value corresponds to a refractive index of 1.291.29, which is closer to water (1.331.33) than glass.

Interesting facts

The refractive index of crown glass is about 1.521.52, while dense flint glass can have a refractive index up to 1.661.66.

Question details

Q32 of 36 questions

Board
CBSE
Class
Class 10
Subject
Science
Year
2015
Section
Section B
Marks
1
Type
MCQ
Chapter
Light — Reflection and Refraction
Topic
Refraction of Light
Bloom's level
Applying
Syllabus topic
Refraction of light through a rectangular glass slab

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Frequently asked questions

How many marks does this question carry in CBSE Class 10 Science 2015?

This question carries 1 mark in the CBSE Class 10 Science 2015 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Light — Reflection and Refraction" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Refraction of Light" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2015 paper?

This is a MCQ question from Section B in the CBSE Class 10 Science 2015 paper.