Question 205 marksLong AnswerSection SECTION-A

Write balanced chemical equations for the following statements:

(i) NaOH\text{NaOH} solution is heated with zinc granules.

(ii) Excess of carbon dioxide gas is passed through lime water.

(iii) Dilute sulphuric acid reacts with sodium carbonate.

(iv) Egg shells are dropped in hydrochloric acid.

(v) Copper (II) oxide reacts with dilute hydrochloric acid.

Acids, Bases and Salts
Chemical Reactions of Acids and Bases

Official answer

The balanced chemical equations for the given statements are:


(i) NaOHNaOH solution is heated with zinc granules:

2NaOH(aq)+Zn(s)→ΔNa2ZnO2(aq)+H2(g)2NaOH(aq) + Zn(s) \xrightarrow{\Delta} Na_2ZnO_2(aq) + H_2(g)

(Product: Sodium zincate and Hydrogen gas)


(ii) Excess of carbon dioxide gas is passed through lime water:

First, lime water turns milky due to the formation of insoluble calcium carbonate:

Ca(OH)2(aq)+CO2(g)→CaCO3(s)+H2O(l)Ca(OH)_2(aq) + CO_2(g) \rightarrow CaCO_3(s) + H_2O(l)

On passing excess carbon dioxide, the milkiness disappears due to the formation of soluble calcium hydrogencarbonate:

CaCO3(s)+H2O(l)+CO2(g)→Ca(HCO3)2(aq)CaCO_3(s) + H_2O(l) + CO_2(g) \rightarrow Ca(HCO_3)_2(aq)


(iii) Dilute sulphuric acid reacts with sodium carbonate:

Na2CO3(s)+H2SO4(aq)→Na2SO4(aq)+H2O(l)+CO2(g)Na_2CO_3(s) + H_2SO_4(aq) \rightarrow Na_2SO_4(aq) + H_2O(l) + CO_2(g)


(iv) Egg shells are dropped in hydrochloric acid:

Egg shells are made of calcium carbonate (CaCO3CaCO_3). The reaction is:

CaCO3(s)+2HCl(aq)→CaCl2(aq)+H2O(l)+CO2(g)CaCO_3(s) + 2HCl(aq) \rightarrow CaCl_2(aq) + H_2O(l) + CO_2(g)


(v) Copper (II) oxide reacts with dilute hydrochloric acid:

CuO(s)+2HCl(aq)→CuCl2(aq)+H2O(l)CuO(s) + 2HCl(aq) \rightarrow CuCl_2(aq) + H_2O(l)

(Product: Copper (II) chloride, which gives a blue-green colour to the solution)

Answer keywords:Sodium zincateCalcium carbonateCalcium hydrogencarbonateEgg shellsCopper (II) chloridebalanced chemical equation

Marking scheme

  1. 1.Balanced equation for NaOHNaOH and ZnZn with correct states and formula of sodium zincate. (1 mark)
  2. 2.Balanced equations for lime water turning milky and then clearing with excess CO2CO_2. (1 mark)
  3. 3.Balanced equation for sodium carbonate and sulphuric acid. (1 mark)
  4. 4.Identify egg shells as CaCO3CaCO_3 and write the balanced equation with HClHCl. (1 mark)
  5. 5.Balanced equation for copper (II) oxide and hydrochloric acid. (1 mark)

Hint

Recall that egg shells are made of calcium carbonate. Remember that passing excess carbon dioxide through lime water dissolves the initial white precipitate.

Quick oral answer

The reaction of zinc with NaOHNaOH produces sodium zincate (Na2ZnO2Na_2ZnO_2) and hydrogen gas. Egg shells contain calcium carbonate, which reacts with HClHCl to release carbon dioxide gas with effervescence.

Common mistakes

  1. 1.Writing incorrect formulas for sodium zincate (Na2ZnO2Na_2ZnO_2) or calcium hydrogencarbonate (Ca(HCO3)2Ca(HCO_3)_2).
  2. 2.Forgetting that egg shells are made of calcium carbonate (CaCO3CaCO_3).
  3. 3.Not writing the second step of the reaction when excess CO2CO_2 is passed through lime water.

Analysis and explanation

  1. Reaction (i): Zinc is an amphoteric metal that reacts with strong bases like sodium hydroxide to form a soluble salt (sodium zincate) and hydrogen gas.
  2. Reaction (ii): Carbon dioxide reacts with lime water (Ca(OH)2Ca(OH)_2) to form a white precipitate of CaCO3CaCO_3. Excess CO2CO_2 converts this precipitate into water-soluble calcium hydrogencarbonate (Ca(HCO3)2Ca(HCO_3)_2), clearing the solution.
  3. Reaction (iii): Metal carbonates react with acids to yield salt, water, and carbon dioxide gas.
  4. Reaction (iv): Egg shells are primarily composed of calcium carbonate (CaCO3CaCO_3). Thus, they react with HClHCl in the same manner as any metal carbonate, producing calcium chloride, water, and carbon dioxide.
  5. Reaction (v): Copper (II) oxide is a basic metal oxide. It reacts with hydrochloric acid to undergo a neutralization-like reaction, forming copper (II) chloride (which turns the solution blue-green) and water.

Interesting facts

The blue-green color of the solution when copper (II) oxide dissolves in hydrochloric acid is due to the formation of Cu2+Cu^{2+} ions in the form of copper (II) chloride.

Question details

Q20 of 36 questions

Board
CBSE
Class
Class 10
Subject
Science
Year
2014
Section
Section SECTION-A
Marks
5
Type
Long Answer
Chapter
Acids, Bases and Salts
Topic
Chemical Reactions of Acids and Bases
Bloom's level
Applying
Syllabus topic
Reactions of acids and bases with metals, metal carbonates, metal oxides

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Frequently asked questions

How many marks does this question carry in CBSE Class 10 Science 2014?

This question carries 5 marks in the CBSE Class 10 Science 2014 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Acids, Bases and Salts" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Chemical Reactions of Acids and Bases" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2014 paper?

This is a Long Answer question from Section SECTION-A in the CBSE Class 10 Science 2014 paper.