Q24
5 marksLong AnswerSection SECTION-A

(i) Establish a relationship to determine the equivalent resistance RR of a combination of three resistors having resistances R1R_1, R2R_2 and R3R_3 connected in parallel.

(ii) Three resistors are connected in an electrical circuit. Calculate the resistance between A and B.

Figure for question 24
Chemical Reactions and Equations
Chemical Reactions and Equations
Official Answer

The correct answer is (a) 4Ω.

parallel resistorsequivalent resistance

Marking Scheme

  • 11/R = 1/R1 + 1/R2 + 1/R3

Hint

Use the formula for parallel resistors: 1/R = 1/R1 + 1/R2 + 1/R3.

Quick Oral Answer

The correct answer is (a) 4Ω. The formula for parallel resistors is 1/R = 1/R1 + 1/R2 + 1/R3.

Analysis & Explanation

The question asks us to establish a relationship to determine the equivalent resistance R of a combination of three resistors having resistances R1, R2, and R3 connected in parallel. We can use the formula: 1/R = 1/R1 + 1/R2 + 1/R3. In this case, the resistors are connected in parallel, so we can add their reciprocals to find the equivalent resistance. The correct answer is (a) 4Ω.

Common Mistakes

  1. 1assuming the resistors are connected in series

Interesting Facts

The formula for parallel resistors is 1/R = 1/R1 + 1/R2 + 1/R3.

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Frequently Asked Questions

How many marks does this question carry in CBSE Class 10 Science 2014?

This question carries 5 marks in the CBSE Class 10 Science 2014 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Chemical Reactions and Equations" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Chemical Reactions and Equations" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2014 paper?

This is a Long Answer question from Section SECTION-A in the CBSE Class 10 Science 2014 paper.