While performing an experiment with raisins, a student took the following measurements: Mass of water taken in the beaker = 25 g, Mass of raisins before soaking = 5 g, Mass of raisins after soaking = 8 g, Mass of water left in the beaker after experiment = 21 g. The percentage of water absorbed by raisins is

The percentage of water absorbed by raisins is calculated using the formula:

$$\text{Percentage of water absorbed} = \frac{\text{Mass of water absorbed}}{\text{Initial mass of dry raisins}} \times 100$$

Given:

• Initial mass of dry raisins ($W_1$) = $5\text{ g}$
• Mass of soaked raisins ($W_2$) = $8\text{ g}$
• Mass of water absorbed = $W_2 - W_1 = (8 - 5)\text{ g}$

Substituting these values into the formula gives:

$$\text{Percentage of water absorbed} = \frac{(8 - 5)\text{ g}}{5\text{ g}} \times 100$$

• Option B is correct because it correctly divides the mass of water absorbed by the initial dry mass of the raisins.
• Option A is incorrect because it uses the total mass of water in the beaker ($25\text{ g}$) as the denominator.
• Option C is incorrect because it uses the mass of water left in the beaker ($21\text{ g}$) as the denominator.
• Option D is incorrect because it uses the final mass of the soaked raisins ($8\text{ g}$) as the denominator instead of the initial dry mass.