Question 143 marksShort AnswerSection A

Distinguish between esterification and saponification reactions of organic compounds with the help of the chemical equation for each. What is the use of (i) esters and (ii) saponification process?

Carbon and its Compounds
Chemical Properties of Carbon Compounds

Official answer

Distinction between Esterification and Saponification


FeatureEsterificationSaponification
DefinitionThe reaction of a carboxylic acid with an alcohol in the presence of an acid catalyst to form a sweet-smelling ester.The reaction of an ester with an alkali (base) to yield back the alcohol and the sodium salt of the carboxylic acid (soap).
ReactantsCarboxylic acid + AlcoholEster + Strong Base (e.g., NaOH\text{NaOH})
ProductsEster + WaterSodium salt of carboxylic acid (Soap) + Alcohol



Chemical Equations


  • Esterification Reaction:

CH3COOH+CH3CH2OH→AcidCH3COOCH2CH3+H2O\text{CH}_3\text{COOH} + \text{CH}_3\text{CH}_2\text{OH} \xrightarrow{\text{Acid}} \text{CH}_3\text{COOCH}_2\text{CH}_3 + \text{H}_2\text{O}

(Ethanoic acid + Ethanol →\rightarrow Ethyl ethanoate + Water)


  • Saponification Reaction:

CH3COOCH2CH3+NaOH→CH3COONa+CH3CH2OH\text{CH}_3\text{COOCH}_2\text{CH}_3 + \text{NaOH} \rightarrow \text{CH}_3\text{COONa} + \text{CH}_3\text{CH}_2\text{OH}

(Ethyl ethanoate + Sodium hydroxide →\rightarrow Sodium acetate + Ethanol)




Uses


  1. Use of Esters: Esters are sweet-smelling substances used in making perfumes, synthetic flavorings, cosmetics, and as industrial solvents.
  2. Use of Saponification Process: This process is primarily used in the commercial preparation and manufacturing of soaps.
Answer keywords:EsterificationSaponificationEthyl ethanoateSodium hydroxideSoapPerfumes

Marking scheme

  1. 1.Correct distinction between esterification and saponification with definitions (1 mark)
  2. 2.Balanced chemical equation for esterification (0.5 marks)
  3. 3.Balanced chemical equation for saponification (0.5 marks)
  4. 4.Stating the use of esters (perfumes/flavoring agents) (0.5 marks)
  5. 5.Stating the use of saponification (soap preparation) (0.5 marks)

Hint

Esterification forms a sweet-smelling ester using an acid catalyst, while saponification uses a base to break down the ester into soap and alcohol.

Quick oral answer

Esterification is the reaction of an alcohol with a carboxylic acid to form a sweet-smelling ester. Saponification is the alkaline hydrolysis of an ester to produce soap and alcohol.

Common mistakes

  1. 1.Writing the saponification equation without a base like NaOH\text{NaOH}.
  2. 2.Confusing the products of the two reactions.

Analysis and explanation

Esterification is a condensation reaction where an ester is synthesized from an organic acid and an alcohol, catalyzed by mineral acids. Saponification is essentially the reverse process (hydrolysis of an ester under basic conditions), which breaks down the ester linkage to produce soap (sodium/potassium salt of fatty acid) and alcohol.

Interesting facts

Saponification gets its name from the Latin word 'sapo', which means soap. Historically, soap was made by boiling animal fats with ashes containing potassium carbonate.

Question details

Q14 of 41 questions

Board
CBSE
Class
Class 10
Subject
Science
Year
2012
Section
Section A
Marks
3
Type
Short Answer
Chapter
Carbon and its Compounds
Topic
Chemical Properties of Carbon Compounds
Bloom's level
Understanding
Syllabus topic
Properties of ethanol and ethanoic acid, esterification and saponification

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Frequently asked questions

How many marks does this question carry in CBSE Class 10 Science 2012?

This question carries 3 marks in the CBSE Class 10 Science 2012 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Carbon and its Compounds" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Chemical Properties of Carbon Compounds" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2012 paper?

This is a Short Answer question from Section A in the CBSE Class 10 Science 2012 paper.