Question 52 marksShort AnswerSection A

(i) How do you calculate the possible valency of an element from the electronic configuration of its atoms?

(ii) Calculate the valency of an element X whose atomic number is 9.

Metals and Non-metals
Valency and Electronic Configuration

Official answer

(i) The valency of an element is determined by the number of valence electrons present in the outermost shell of its atom:

  • If the number of valence electrons is 1,2,3,1, 2, 3, or 44, the valency is equal to the number of valence electrons.
  • If the number of valence electrons is 5,6,7,5, 6, 7, or 88, the valency is calculated as 8−number of valence electrons8 - \text{number of valence electrons}.

(ii) For element X with atomic number 99:

  • Electronic configuration: 2,72, 7
  • Number of valence electrons = 77
  • Valency = 8−7=18 - 7 = 1
Answer keywords:valence electronsoutermost shellelectronic configurationvalencyoctet

Marking scheme

  1. 1.Stating the rule for calculating valency when valence electrons are ≤4\le 4 and >4> 4. (1 mark)
  2. 2.Writing the electronic configuration of element X (2,72, 7) and calculating its valency as 11. (1 mark)

Hint

Write the electronic configuration of the element with atomic number 99 by distributing electrons in K and L shells, then subtract the outermost electrons from 88.

Quick oral answer

The valency of an element with atomic number 99 is 11 because its electronic configuration is 2,72, 7, and it needs only 11 electron to complete its octet.

Common mistakes

  1. 1.Students often confuse valence electrons with valency and write the valency of element X as 77 instead of 11.
  2. 2.Incorrect distribution of electrons in shells.

Analysis and explanation

Valency represents the combining capacity of an atom to achieve a stable octet configuration. For elements with 11 to 44 valence electrons, it is easier to lose these electrons to achieve stability, so their valency equals their valence electron count. For elements with 55 to 77 valence electrons, it is easier to gain electrons (8−valence electrons8 - \text{valence electrons}) to complete their octet.

Interesting facts

Element X with atomic number 99 is Fluorine, which is the most electronegative and reactive non-metal in the periodic table.

Question details

Q5 of 36 questions

Board
CBSE
Class
Class 10
Subject
Science
Year
2011
Section
Section A
Marks
2
Type
Short Answer
Chapter
Metals and Non-metals
Topic
Valency and Electronic Configuration
Bloom's level
Applying
Syllabus topic
Inert gas configuration, transfer of electrons, formation and properties of ionic compounds

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Frequently asked questions

How many marks does this question carry in CBSE Class 10 Science 2011?

This question carries 2 marks in the CBSE Class 10 Science 2011 examination.

Which chapter does this question come from in Science?

This question is from the chapter "Metals and Non-metals" in the CBSE Class 10 Science syllabus.

What topic does this question cover in Science?

This question covers the topic "Valency and Electronic Configuration" from CBSE Class 10 Science.

What type of question is this in the CBSE Class 10 Science 2011 paper?

This is a Short Answer question from Section A in the CBSE Class 10 Science 2011 paper.