(i) How do you calculate the possible valency of an element from the electronic configuration of its atoms?
(ii) Calculate the valency of an element X whose atomic number is 9.
(i) How do you calculate the possible valency of an element from the electronic configuration of its atoms?
(ii) Calculate the valency of an element X whose atomic number is 9.
Official answer
(i) The valency of an element is determined by the number of valence electrons present in the outermost shell of its atom:
- If the number of valence electrons is or , the valency is equal to the number of valence electrons.
- If the number of valence electrons is or , the valency is calculated as .
(ii) For element X with atomic number :
- Electronic configuration:
- Number of valence electrons =
- Valency =
Marking scheme
- 1.Stating the rule for calculating valency when valence electrons are and . (1 mark)
- 2.Writing the electronic configuration of element X () and calculating its valency as . (1 mark)
Hint
Write the electronic configuration of the element with atomic number by distributing electrons in K and L shells, then subtract the outermost electrons from .
Quick oral answer
The valency of an element with atomic number is because its electronic configuration is , and it needs only electron to complete its octet.
Common mistakes
- 1.Students often confuse valence electrons with valency and write the valency of element X as instead of .
- 2.Incorrect distribution of electrons in shells.
Analysis and explanation
Valency represents the combining capacity of an atom to achieve a stable octet configuration. For elements with to valence electrons, it is easier to lose these electrons to achieve stability, so their valency equals their valence electron count. For elements with to valence electrons, it is easier to gain electrons () to complete their octet.
Interesting facts
Element X with atomic number is Fluorine, which is the most electronegative and reactive non-metal in the periodic table.
Question details
Q5 of 36 questions
- Board
- CBSE
- Class
- Class 10
- Subject
- Science
- Year
- 2011
- Section
- Section A
- Marks
- 2
- Type
- Short Answer
- Chapter
- Metals and Non-metals
- Topic
- Valency and Electronic Configuration
- Bloom's level
- Applying
- Syllabus topic
- Inert gas configuration, transfer of electrons, formation and properties of ionic compounds
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Frequently asked questions
How many marks does this question carry in CBSE Class 10 Science 2011?
This question carries 2 marks in the CBSE Class 10 Science 2011 examination.
Which chapter does this question come from in Science?
This question is from the chapter "Metals and Non-metals" in the CBSE Class 10 Science syllabus.
What topic does this question cover in Science?
This question covers the topic "Valency and Electronic Configuration" from CBSE Class 10 Science.
What type of question is this in the CBSE Class 10 Science 2011 paper?
This is a Short Answer question from Section A in the CBSE Class 10 Science 2011 paper.