Draw the structure for ethanoic acid molecule, .
Draw the structure for ethanoic acid molecule, .
The structure of ethanoic acid () consists of a methyl group () bonded to a carboxyl group (). The first carbon atom is bonded to three hydrogen atoms, and the second carbon atom is double-bonded to one oxygen atom and single-bonded to a hydroxyl group ().
Marking Scheme
- 10.5 marks for the correct methyl group () representation.
- 20.5 marks for the correct carboxyl group () representation with the double bond.
Hint
Remember that Carbon forms four bonds. One Carbon is part of the methyl group, and the other is part of the functional group containing a double bond to Oxygen.
Quick Oral Answer
Ethanoic acid has the formula . It contains two carbon atoms: one in a methyl group and one in a carboxylic acid functional group.
Analysis & Explanation
Ethanoic acid is a carboxylic acid. In its structure, the carbon of the carboxyl group () undergoes hybridization to form a double bond with one oxygen and a single bond with the group. The other carbon is part of a methyl group () with hybridization.
Common Mistakes
- 1Drawing a single bond between Carbon and the first Oxygen in the carboxyl group.
- 2Forgetting the Hydrogen atom attached to the Oxygen in the hydroxyl group.
Interesting Facts
Ethanoic acid is commonly known as acetic acid and is the primary ingredient in vinegar (typically 5-8% by volume).
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Frequently Asked Questions
How many marks does this question carry in CBSE Class 10 Science 2011?
This question carries 1 mark in the CBSE Class 10 Science 2011 examination.
Which chapter does this question come from in Science?
This question is from the chapter "Chemical Reactions and Equations" in the CBSE Class 10 Science syllabus.
What topic does this question cover in Science?
This question covers the topic "Carbon and its Compounds" from CBSE Class 10 Science.
What type of question is this in the CBSE Class 10 Science 2011 paper?
This is a Very Short Answer question from Section A in the CBSE Class 10 Science 2011 paper.