Question 81 markMCQSection A

The mid-point of the line segment joining the points (5,−4)(5, -4) and (6,4)(6, 4) lies on :

(a) x-axis (b) y-axis (c) origin (d) neither x-axis nor y-axis

Coordinate Geometry
Coordinate Geometry - Midpoint Formula

Options

(A)x-axis
(B)y-axis
(C)origin
(D)neither x-axis nor y-axis

Official answer

(a) x-axis — the midpoint is (5.5,0)(5.5, 0); since its y-coordinate is 0, it lies on the x-axis.

Answer keywords:midpoint formulacoordinate geometryx-axissection formulay-coordinate zero

Marking scheme

  1. 1.1 mark: correct option (a) x-axis; full working credit: midpoint = (5.5,0)(5.5, 0), and since y-coordinate = 0, it lies on the x-axis.

Hint

Apply the midpoint formula and check which coordinate becomes zero — if y=0y = 0, the point lies on the x-axis.

Quick oral answer

The midpoint of (5,−4)(5,-4) and (6,4)(6,4) is (5.5,0)(5.5, 0); since its y-coordinate is zero, the point lies on the x-axis.

Common mistakes

  1. 1.Confusing which axis corresponds to y=0y = 0 versus x=0x = 0 (mixing up x-axis and y-axis).
  2. 2.Averaging the coordinates incorrectly, e.g., adding instead of dividing by 2.
  3. 3.Assuming the point is the origin just because one coordinate is zero, without checking the other coordinate.

Analysis and explanation

Tests the midpoint formula and recognition of points lying on the coordinate axes.


Concept

  • Midpoint of segment joining (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is M=(x1+x22,y1+y22)M = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right).
  • A point lies on the x-axis exactly when its y-coordinate is 0.

Key points

  • M=(5+62,−4+42)M = \left(\frac{5+6}{2}, \frac{-4+4}{2}\right) = (5.5,0)(5.5, 0).
  • Since y=0y = 0 (and x≠0x \ne 0), the point lies on the x-axis — option (a).

Common mistakes

  • Swapping which axis corresponds to y=0y = 0 vs x=0x = 0 (y=0y = 0 is the x-axis, not the y-axis).
  • Assuming (5.5,0)(5.5, 0) is the origin, which requires both coordinates to be 0.

Interesting facts

The midpoint formula is a direct special case (k=1k=1) of the section formula, which was systematically developed in coordinate geometry by René Descartes in the 17th century.

CBSE Class 10 sample papers regularly test the midpoint formula as a 1-mark MCQ because it combines arithmetic accuracy with conceptual understanding of axes.

Question details

Q8 of 56 questions

Board
CBSE
Class
Class 10
Subject
Mathematics (Standard)
Year
2026
Section
Section A
Marks
1
Type
MCQ
Chapter
Coordinate Geometry
Topic
Coordinate Geometry - Midpoint Formula
Bloom's level
apply
Syllabus topic
Unit 3: Coordinate Geometry — Section Formula (Midpoint as special case)
Author
CBSE
Reviewed by
Padhantu Academic Team

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Frequently asked questions

What is the midpoint formula?

For points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2), the midpoint is (x1+x22,y1+y22)\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right).

How do you know if a point lies on the x-axis or y-axis?

A point lies on the x-axis if its y-coordinate is 0, and on the y-axis if its x-coordinate is 0.